Question

Xsquare +x-6=0 find the roots of the quadratic equation

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\sf x=-3 \ OR \ x=2}$

Step-by-step explanation:

Given :

x² + x - 6 = 0

$\sf x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

We have :

a = 1

b = 1

c = - 6

$\sf x=\dfrac{-1\pm\sqrt{1^2-4\times1\times-5}}{2\times1}$

$\sf x=\dfrac{-1\pm\sqrt{25}}{2}$

$\sf x=\dfrac{-1\pm5}{2}$

Values of x are as :

$\sf x=\dfrac{-1+5}{2}$

$\sf x=\dfrac{4}{2}$

$\sf x=2$

$\sf OR$

$\sf x=\dfrac{-1-5}{2}$

$\sf x=\dfrac{-6}{2}$

$\sf x=-3$

$\display \text{{Therefore, we get answer.}}$