Math, asked by ravindarreddy533, 5 months ago

xsquare-x-6 and x square+3a-18 have common factor (x-a) and find value of a​

Answers

Answered by Anonymous
3

Answer:

Value of a is 3.

Step-by-step explanation:

Given that x²-x-6 and x²+3a-18 have a common factor as ( x-a ) .So , firstly on equating x-a with 0 , we get ;

=>x-a=0

=>x=0+a.

=>x=a .

Hence x=a is a zero of both quadratic polynomials.

Put x=a in -x-6 :-

=>p(x) = x²-x-6.

=>p(a) = a²-a-6 = 0.

=>a²-a-6 = 0 .

=>a²-3a+2a-6 = 0.

=>a(a-3)+2(a-3) = 0.

=>( a-3 )( a+2 ) = 0.

=> a = 3,(-2) ..................(i)

Put x=a in +3a-18 :-

=>p(x,a) = x²+3a-18.

=>p(a) = a²+3a-18 = 0.

=>a²+3a-18 = 0.

=>a²+6a-3a-18 = 0.

=>a(a+6)-3(a+6)=0.

=>( a-3 )( a+6 ) = 0.

=>a = 3,(-6)..................(ii)

From (i) and (ii) , a = 3 is common solution to both equations .

Hence the value of a is 3 .

Answered by PhysicistSam
2

Answer:

3

Step-by-step explanation:

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