Question

xsquare-x-6 find sum,zeroes,a and product​

Answer 1

Answer:

sum of zeroes=1

product of zeroes=-6

Step-by-step explanation:

sum of zeroes=-coefficient of x/coefficient of x^2

=-(-1)/1=1

product of roots=constant term/coefficient of x^2

=-6/1

=-6

Answer 2

Question:

Find the zeroes, sum of zeroes and product of zeroes of the following polynomial.

${x}^{2} - x - 6$

Solution:

To find the zeroes of p(x)

p(x) = 0

$p(x) = {x}^{2} - x - 6 =0 \\ \implies{x}^{2} -3x +2x -6 = 0 \\ \implies x(x-3)+2(x-3) = 0 \\ \implies (x+2)(x-3) = 0$

x + 2 = 0

x = -2

x - 3 = 0

x = 3

Zeros of $p(x) = {x}^{2} - x - 6 =0$ are -2 and 3.

Sum of zeroes = -2 + 3 = 1

Sum of zeroes = $\dfrac{-Coefficient \: of \: x}{Coefficient \: of \: {x}^{2}}$

$= \dfrac{-(-1)}{1} = 1$

Product of zeroes = -2 × 3 = -6

Product of zeroes = $\dfrac{Constant \: term}{Coefficient \: of \: {x}^{2}}$

$= \dfrac{-6}{1} = -6$