xsquare2 +x-5 PLEASE ANSWER MY QUESTION
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Step-by-step explanation:
GIVEN:−
x² + 2x - 5 = 0
So, we have to find to it's zeroes by using completing Square method.
x² + 2x - 5 = 0
we can write 2x = 2(x)(1)
x² + (2)(x)(1) + [ 1² - 1²] - 5 = 0
(x + 1)² - 1 - 5 = 0
[(x² + 2x + 1) = (x + 1)² , where, (a² + b² + 2ac = (a + b)²]
so,
(x + 1)² = 6
[taking Square Root both side]
(x + 1) = ±√6
now there is two situation
( 1 ) we have to take (+ve) sign.
So, answeer will be.
(x + 1) = √6
x = (√6 - 1)
( 2 ) we have to take (+ve) sign.
So, answeer will be.
(x + 1) = -√6
x = -(√6 + 1)
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