Math, asked by mamtagiri92, 1 year ago

xsqure +1/×square =3 fine the value of x-1/×​

Answers

Answered by shadowsabers03
1

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$$Answer:$\ \bold{\pm 1}

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x^2+\frac{1}{x^2}=3 \\ \\ x^2+\frac{1}{x^2}-2=3-2 \\ \\ x^2+\frac{1}{x^2}-(2 \times x \times \frac{1}{x})=1 \\ \\ (x-\frac{1}{x})^2=1 \\ \\ x-\frac{1}{x}=\sqrt{1} \\ \\ x+\frac{1}{x}=\bold{\pm1}

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\bold{TO\ REMEMBER...} \\ \\ \\ $If$ \\ \\ x^2+\frac{1}{x^2}=k, \\ \\ $then$ \\ \\ x+\frac{1}{x}=\pm \sqrt{k+2} \\ \\ \& \\ \\ x-\frac{1}{x}=\pm \sqrt{k-2}

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$$Here,$ \\ \\ x^2+\frac{1}{x^2}=3 \\ \\ \\ k=3 \\ \\ \\ $To find$:\ x-\frac{1}{x}. \\ \\ $So use the second one. \\ \\ \\ \pm\sqrt{k-2} \\ \\ \pm\sqrt{3-2} \\ \\ \pm\sqrt{1} \\ \\ \bold{\pm1}

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$$Thank you. Have a nice day. :-)$ \\ \\ \\ \#adithyasajeevan \\ \\ \\

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