xsqure+2x-5=0 solve by completing square method
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Hey!!!
_________
We have
=> x² + 2x - 5 = 0
By Completing the square method
=> x² + 2x = 5
=> x² + 2x + (1)² = 5 + 1
=> (x + 1)² = 6
=> x + 1 = +-√6
Now
=> x + 1 = √6 or x + 1 = -√6
=> x = √6 - 1 or => x = -(√6 + 1)
__________
Hope this helps ✌️
Good Night :-)
_________
We have
=> x² + 2x - 5 = 0
By Completing the square method
=> x² + 2x = 5
=> x² + 2x + (1)² = 5 + 1
=> (x + 1)² = 6
=> x + 1 = +-√6
Now
=> x + 1 = √6 or x + 1 = -√6
=> x = √6 - 1 or => x = -(√6 + 1)
__________
Hope this helps ✌️
Good Night :-)
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