xsqure +ysqure =27xy then show that log [x-y/5]=1/2[logx+logy]
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Answer:
x²+y²=27xy
subtract 2xy on both sides
x²+y²-2xy=25xy
(x-y)²=25xy
(x-y)²/5²=xy
apply log on both sides
2log(x-y)/(5)=logx+logy
log (x-y/5)=1/2(logx+logy)
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