Question

xsqure +ysqure =27xy then show that log [x-y/5]=1/2[logx+logy]​

Answer 1

Answer:

x²+y²=27xy

subtract 2xy on both sides

x²+y²-2xy=25xy

(x-y)²=25xy

(x-y)²/5²=xy

apply log on both sides

2log(x-y)/(5)=logx+logy

log (x-y/5)=1/2(logx+logy)

mark it as brainliest answer