Question

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Answer 1

heya...!!!!


we know that:-

sin(90° + ∅) = cos∅
sin(180 + ∅) = -sin∅
sin(-∅) = -sin∅
tan(90 + ∅) = -cot∅


$\frac{cos( \alpha )}{sin(90+ \alpha )} + \frac{sin( - \alpha )}{sin(180 + \alpha )} - \frac{tan(90 + \alpha )}{cot \alpha } \\ \\ = > \frac{cos \alpha }{ \cos \alpha } + \frac{ - sin \alpha }{ - sin \alpha } - \frac{ - cot \alpha }{ \cot \alpha } \\ \\ = > 1 + 1 + 1 = 3$

Answer 2

after solving given equation we will get :-

cos ¢ -. sin ¢. - cot ¢
____. ____. _____

cos ¢. cos ¢. cot ¢
= 1+1+1
=3
..


hope it helped u