Math, asked by sampannadah007, 9 days ago

xtan(180° − θ). cos(270° + θ) − cosec(90° − θ). sec(180° + θ) = 0

Answers

Answered by pratyakshprakhar
1

Answer:

(note : I am using a instead of thetha)

x tan(180 - a) * cos (270+ a) - cosec (90-a) *sec (180 +a)

= -x tan a * sin a + sec a * sec a

= - x sin ^2 a / cos a + sec ^2 a

= (-x sin^2 a cos a + 1 ) / cos ^ 2 a

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Step-by-step explanation:

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