Question

(xtan(y/x) -ysec²(y/x) )dx-x sec²(y/x) dx=0 solution of this on image
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Answer 1

Answer:

MATHS

Solve sec 2 xtanydy+sec 2 ytanxdx=0

ANSWER:-

Simplifying sec 2

xtanydy+sec 2ytanxdx=0

sec 2

xtanydy=−sec 2

ytanxdxsec 2

2ytany dy=− sec 2 xtanx dx

sec 2 ytany dy=− sec 2 xtanx dx

cos 2 y1

cosysiny

dy=− cos 2 x1

cosxsinx

dx

cosysinydy=−sinxcosxdx

∫cosysinydy=−∫sinxcosxdx

Putt=siny,dt=cosydy

And, u=cosx,du=−sinxdx

∫tdt=∫udu

2t 2 = 2u 2 +c

2sin 2y = 2cos 2

sin 2y−cos 2

x=0

Answered By

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Explanation:

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