Question

xvii) a2+b2 +2(ab+bc+ca)​

Answer 1

Answer:

= a? + b2 + 2ab + 2bc + 2ca

Using identity a2 + b2 + 2ab = (a +

b)2

We get,

= (a + b)² + 2bc + 2ca =

= (a + b)2 + 2c (b + a)

or (a + b)2 + 2c (a + b)

Taking (a + b) common

(a + b)(a + b + 2c)

: a? + b2 + 2 (ab + bc + ca) = (a + b) .. (a + b + 2c)

Answer 2

Answer:

(a+b)(a+b+2c)

Step-by-step explanation:

a2+b2+2ab=(a+b)2

(a+b)2+2bc+2ca

(a+b)2+2c(a+b)

(a+b)(a+b+2c)