Math, asked by lousistron2609, 1 year ago

Xxxa is divisible by 9, what is the least natural no at a?

Answers

Answered by aquialaska
0

Answer:

Least natural no at a is 3

Step-by-step explanation:

We are given that xxxa is divisible by 9

To find: least natural no at a

Divisibility rule of 9 states that if sum of digits of no. is divisible by 9 then no. is divisible by 9.

Since x & a are digits, It only takes value from 0 - 9

Case 1,

when x = 1

we have 111a

sum of digits = 1 + 1 + 1 + a = 3 + a

3 + a is divisible by 9

⇒ a = 6

Case 2,

when x = 2

we have 222a

sum of digits = 2 + 2 + 2 + a = 6 + a

6 + a is divisible by 9

⇒ a = 3

Case 3,

when x = 3

we have 333a

sum of digits = 9 + a

9 + a is divisible by 9

⇒ a = 0

Case 4,

when x = 4

we have 444a

sum of digits = 12 + a

12 + a is divisible by 9

⇒ a = 6

Case 5,

when x = 5

we have 555a

sum of digits = 15 + a

15 + a is divisible by 9

⇒ a = 3

Case 6,

when x = 6

we have 666a

sum of digits = 18 + a

18 + a is divisible by 9

⇒ a = 0

Case 7,

when x = 7

we have 777a

sum of digits = 21 + a

21 + a is divisible by 9

⇒ a = 6

Case 8,

when x = 8

we have 888a

sum of digits = 24 + a

24 + a is divisible by 9

⇒ a = 3

Case 9,

when x = 9

we have 999a

sum of digits = 27 + a

27 + a is divisible by 9

⇒ a = 0

Therefore, Least natural no at a is 3

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