Question

xy=3

(x-1)(y+2)=15
simultaneous equations
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Answer 1

Answer:

given,  xy=3 ; (x-1)(y+2) = 15

(x-1)(y+2) = 15

xy+2x-y-2=15              

3+2(3/y)-y-2=15                             [ ∵ xy=3 => x=3/y]

(6/y)-y = 14

(6-y²)/y =14

6-y² = 14y

    0 = y²+14y-6                  ∵ on soving this equation

y=0.416

hence x= 3/y = 7.211