(xy + 3)(x2y2 – 2) + 6 for x = 1, y = -1
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At x = 1 and y = - 1
( xy + 3 ) ( x²y² - 2 )
( 1 x - 1 + 3 ) ( 1² (-1)² - 2 )
( - 1 + 3 ) ( 1 - 2 )
2 x - 1
Answer ➡ - 2
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