Question

xy=-30 and x2+y2=61 then find the value of (x+y)

Answer 1

Hlo friend.. Cutiepie Here..

Here is ur answer :

x² + y² = 61

xy = - 30

( x + y) ² = x² + y² + 2 ( xy)

( x + y )² = 61 + 2 × - 30

( x + y )² = 61 + ( - 60)

( x + y)² = 61 - 60 = 1

( x - y) = square root of 1

( x - y) = 1

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HOPE IT HELPS YOU..

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Answer 2

Answer:

The value of $x + y = +1 , -1.$

Step-by-step explanation:

$(x+y)^{2} = x^{2} +y^{2} +2xy\\Given \\x^{2} +y^{2} = 61, xy = - 30 .\\(x+y)^{2} = 61 +2(-30)\\(x+y)^{2} = 61-60\\(x+y)^{2} = 1\\(x+y)^{} = +1 ,-1$

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