Xy and bd are parralel lines x is point on ab and c is a point on bd xb=xc work out angle bxc give a reason for each angle you work out
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Given:
Xy and bd are parralel lines x is point on ab and c is a point on bd.
xb=xc.
To Find:
Angle bxc.
Solution:
We can see that XY is parallel to BD.
AB is a line intercepting both these lines.
Therefore,
- ∠AXY = ∠XBC , as they are corresponding angles.
- ∠XBC = 55°.
Now for other angles,
ΔXBC is isosceles triangle.
- ∠XBC = ∠XCB
- ∠XCB= 55°
- ∠CXB = 180° - 2 x 55° = 70°
Also ∠AXY +∠YXC + ∠CXB = 180°
Therefore
- ∠YXC = 180° - 70° - 55° = 55°
Now,
- ∠XCD = ∠CBX + ∠CXB ,
- Exterior angle of a triangle is the sum of internal opposite angles.
- ∠XCD = 125°
Therefore, ∠BXC = 55°
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