XY and MN intersect at O.if POY = 90 and a:b = 4:5 show that angle c = 130
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Let ∠ a = 2x, then ∠b = 3x
(sum of angle in linear pair always equal to 180° )
∠XOM + ∠MOP + ∠POY = 180°
∠b + ∠a + ∠POY = 180°
given that ∠POY = 90°
plug this value we get
3x + 2x + 90° = 180°
5x = 90°
x = 18°
a = 2x = 2 × 18 = 36°
b = 3x = 3 ×18 = 54°
MN is a straight line.
sum of angle in linear pair always equal to 180°
so that ∠b + ∠c = 180°
54° + ∠c = 180°
∠c = 180° − 54° = 126°
∠ c = 126°
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