Math, asked by ishitasinghai, 6 months ago

XY and X’ Y’ are the parallel tangent to a circle with the centre “O” and another tangent AB with the point of contact “C” intersecting XY at A and X’ Y’ at B. Prove that ∠AOB is 90°. (OR) AB is a diameter of circle. P is a point on the semi circle APB . AH and BK are the perpendiculars from A and B respectively to the tangent at P . Prove that : AH+BK=AB

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Answers

Answered by helloooooooooo
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Answer:

with the point of contact “C” intersecting XY at A and X’ Y’ at B. Prove that ∠AOB is 90°. (OR) AB is a diameter of circle. P is a point on the semi circle APB . AH and BK are the perpendiculars from A and B respectively to the tangent at P . Prove

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