Question

xy=log x/y + 2log2=2; find x and y
x>0 ; y>0

Answer 1

Step-by-step explanation:

xy = log(x/y.4)=2

xy=2 equ. --(1.)

4x=100y

x=25y ---equ. (2.)

from equ(1.) and (2.)

25y^2 =2

y= √2/5

x=5√2

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