Question

xy-x-2y=6.
What is x,y?

Answer 1

Answer:

Step-by-step explanation:

We Have :-

xy - x - 2y = 6

To Find :-

x and y

Solution :-

xy - x - 2y = 6

Adding 2 on both sides

xy - x - 2y + 2 = 6 + 2

x ( y - 1 ) - 2 ( y - 1 ) = 8

( y - 1 ) ( x - 2 ) = 8

Now we can find values of x and y by hit and trial method

Answer 2

Correct Question :-- xy-x+2y=6. What is x,y ? (where x and y are real numbers ).

Solution :---

→ xy-x+2y = 6

Taking All to LHS side ,

→ xy - x + 2y - 6 = 0

Splitting 6 now,

→ xy - x + 2y - 2 - 4 = 0

→ xy - x + 2y - 2 = 4

→ x(y-1) + 2(y - 1) = 4

Taking (y-1) common now,

→ (y-1) (x+2) = 4

Now, lets assume,

→ (y-1) = m

→ (x+2) = n

Than ,

→ m * n = 4

→ m and n can be = (1,4) (4,1) (2,2) , (-1,-4)(-4,-1)

Putting all Equal now, we get,

→ if y-1 = 1 than, x+2 = 4

→ y = 2 and, x = 2 . ( First value )

Similarly,

→ if y-1 = 4 , than, x + 2 = 1

→ y = 5 , and x = (-1) (Second value ) .

Similarly,

→ if y-1 = 2 and x+2 = 2

→ y = 3 and, x = 0 (Third value).

Similarly,

→ if y-1 = (-1) than, x+2 = (-4)

→ y = 0 and x = (-6) (Fourth value).

Similarly,

→ if y-1 = (-4) than , x+2 = (-1)

→ y = (-3) and, x = (-3) (Fifth value).

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So, we can say that, all Possible values of x and y, when both are real numbers are = (2,2) , (5,-1) , (3,0) , (0,-6) ans (-3,-3) Respectively ..