Xy(x+y)=1 1/x³y³-x³-y³=?
Answers
Answered by
0
Answer:
We know that,
x³-y³=(x-y)(x²+xy+y²)......................1
Given that,
x/y+y/x= -1
(x²+y²)/xy= -1
x²+y²= -xy
x²+y²+xy = 0
(x²+xy+y²) = 0
Multyplying by (x-y) on both sides we get,
(x-y)(x²+xy+y²)=(x-y)×0
By eq1 we get,
x³-y³=0
Hence x³-y³=0
JAI SHREE KRISHNA
Answered by
0
Answer:
x/y+y/x= -1
(x²+y²)/xy= -1
x²+y²= -xy
x²+y²+xy = 0
(x²+xy+y²) = 0
Multyplying by (x-y) on both sides we get,
(x-y)(x²+xy+y²)=(x-y)×0
By eq 1 we get,
x³-y³=0
Hence x³-y³=0
Explanation:
Similar questions