Question

xy+x+y=1332,yz+y+z=300,xz+x+z=216 then x+y+z=?

Answer 1

xy+x+y+1=1333......... (1)
yz+y+x+1=301............ (2)
xz+x+z+1=217.............. (3)

(1)(x+1)(y+1)=1333
(2)(y+1)(z+1)=301
(3)(z+1)(x+1)=217

(x+1)(y+1)(z+1)=9331

x+1=9331÷301=31 x=30
y+1=9331÷217=43 y=42
z+1=9331÷1333=7 z=6

x+y+z=30+42+6=78
PLEASE MARK THE ANSWER AS BRSINLIEST.