xy(x+y)=2 then dy/dx=? PLEASE SOLVE IT FRIENDS
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hello friend..!!
to find dy/dx in the above question,
it is given that , xy( x + y ) = 2
⇒ x²y + y²x = 2
⇒ (x²y) + (xy²) = (2)
⇒ x² + 2xy + 2xy + y² = 0
⇒ x² + 2xy + 2xy + y² = 0
⇒ ( x² + 2xy ) = - ( 2xy + y² )
⇒ = - ( 2xy + y² ) / x² + 2xy .
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hope it is useful...!!
to find dy/dx in the above question,
it is given that , xy( x + y ) = 2
⇒ x²y + y²x = 2
⇒ (x²y) + (xy²) = (2)
⇒ x² + 2xy + 2xy + y² = 0
⇒ x² + 2xy + 2xy + y² = 0
⇒ ( x² + 2xy ) = - ( 2xy + y² )
⇒ = - ( 2xy + y² ) / x² + 2xy .
-------------------------------------------------------------------
hope it is useful...!!
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