Math, asked by RiddhiThacker98798, 10 months ago

xy/x+y = 5/6second equation xy/x-y = 6 solve the equation in elimination method

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Answered by Natsukαshii
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Answered by Anonymous
5

AnswEr

The value of

x = 60/31

y = 60/41

Given

The equations are :

  •  \sf{ \frac{xy}{x + y}  =  \frac{5}{6} }
  •  \sf{ \frac{xy}{x - y}  = 6}

To Find

  • The value of x and y

Solution

 \sf{ \frac{xy}{x + y}  =  \frac{5}{6} }

  \sf{\implies \frac{x + y}{xy}  =  \frac{6}{5} }

  \sf{ \implies\frac{1}{y}  +  \frac{1}{x}  =  \frac{6}{5} -  -  - (1) }

And the other one

 \sf{ \frac{xy}{x - y}  = 6}

  \sf{ \implies\frac{x - y}{xy}  =  \frac{1}{6}}

 \sf{ \implies  \frac{1}{y}  -  \frac{1}{x}  =  \frac{1}{6}  -  -  - (2)}

Let us consider 1/x = p and 1/y = q so that the equations (1) and (2) becomes

 \sf{q + p  =  \frac{6}{5} -  -  - (3) }

and

 \sf{ \implies q - p =  \frac{1}{6}  -  -  - (4)}

Adding equation (3) and (4) we have

 \sf{q + p + q- p=  \frac{6}{5}  +  \frac{1}{6} }

  \sf{\implies 2q=  \frac{5 + 36}{30} }

 \sf{\implies q=  \frac{41}{30 \times 2} }

 \sf{ \implies q=  \frac{41}{60} }

And Using the value of q in (4)

 \sf{  \implies   \frac{41}{60} - p  =  \frac{1}{6} }

 \sf{ \implies  - p=  \frac{1}{6}   -   \frac{41}{60} }

 \sf{ \implies p=  \frac{31}{60} }

Since p = 1/x

 \sf{\implies \frac{1}{x}  =  \frac{31}{60} }

 \boxed{\sf{ \implies x =  \frac{60}{31} }}

And q = 1/y

 \sf{ \implies  \frac{1}{y} =  \frac{41}{60} }

 \boxed{ \sf{ \implies y =  \frac{60}{41} }}

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