Question

xy/x+y =a xz/x+z=bandyz/y+z=c where a b c are other than zero then x equals

Answer 1

Answer:

Step-by-sso we can rewrite xy/(x+y) = a  

as  

1/x+1/y = 1/a (1)  

also rewrite xz/(x+z) = b  

as  

1/x+1/z = 1/b (2)  

add (1) and (2)  

==> 2/x+1/y+1/z = 1/a+1/b  

but we also know that 1/z+1/y = 1/c  

so 2/x+1/c = 1/a+1/b  

so 2/x = 1/a+1/b-1/c = (bc+ac-ab)/abc  

so x = 2abc / (bc+ac-ab)  

QED tep explanation: