) (xy +yz + xz) x (x + y + z)
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Step-by-step explanation:
starting with
xy +yz +x’z
Using 1 = 1 + a
xy + yz + x’z = xy(1 + z) +yz + x’z(1 +y)
expand it out
xy + xyz + yz + x’z + x’zy = xy + yz( x + x’) + yz + x’z
and since (x + x’) =1
= xy + yz(x + x’) + yz + x’z
the yz terms is extra and can be eliminated
= xy + yz(x + x’) + x’z
and since yz(x + x’) come from xy and x’z
= xy + x’z
it might be easier to draw a K map
x y and z
………..0 …. 1
0 0……..……A
01……...…….A.b
11……C…….C,b
1 0…………………
A = x’z
b = yz
C = xy
The b term is extraneous
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