xy [yz – zx – {yx – (3y – xz) – (xy – zy)}]
There is no '-' after xy
And can anyone tell if I am right
xy [yz – zx – {yx – (3y – xz) – (xy – zy)}]
=xy [yz – zx – {yx -3y + xz -xy +zy} (yx n -xy are cancelled)
=xy [yz – zx+3y-xz-zy]
=xy [3y-2zx]
=3xy^2-2x^2yz
Answers
Answered by
3
Answer:
xy−[yz−zx−yx−(3y−xz)−(x−y−2y)]
=xy−[yz−zx−yx−3y+xz−x+y+2y]
=xy−[yz−yx−x]
=xy−yx+xy+x
=2xy−yx+x
Step-by-step explanation:
xy−[yz−zx−yx−(3y−xz)−(x−y−2y)]
=xy−[yz−zx−yx−3y+xz−x+y+2y]
=xy−[yz−yx−x]
=xy−yx+xy+x
=2xy−yx+x
Similar questions