Question

xy(z? + 1) + z(x² + y2) can be factorised as
(a) (xy +z) (yz + x)
(b) (zx + y) (xy + z)
(c) (yz + x) (zx + y) (d) (x² + y2) (z + x)​

Answer 1

Answer:

xy(z2+1) + z(x2+y2)

xyz2+xy +x2z+y2z

Rearranging The Terms

xyz2+x2z+xy+y2z

xz(yz+x)+y(x+yz)

(xz+y)(x+yz)

Step-by-step explanation:

hope it helps you