xy2 = 2x (4x2 - 9y2)
= 2x [(2x)2 – (3y)?]
= 2x (2x + 3y) (2x - 3y)
-36 = 3 (x2 + 4x – 12)
= 3 (x2 + 6x - 2x – 12)
3 [x(x + 6) -2(x + 6)]
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Answered by
2
Answer:
Answer is 3x square + 12x - 36
Step-by-step explanation:
U already solve this
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Answered by
1
Answer:
u already slove this problem
Step-by-step explanation:
= 2x (4x2 - 9y2)
= 2x [(2x)2 – (3y)?]
= 2x (2x + 3y) (2x - 3y)
-36 = 3 (x2 + 4x – 12)
= 3 (x2 + 6x - 2x – 12)
3 [x(x + 6) -2(x + 6)]
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