Question

xy2 = 2x (4x2 - 9y2)
= 2x [(2x)2 – (3y)?]
= 2x (2x + 3y) (2x - 3y)
-36 = 3 (x2 + 4x – 12)
= 3 (x2 + 6x - 2x – 12)
3 [x(x + 6) -2(x + 6)]​

Answer 1

Answer:

Answer is 3x square + 12x - 36

Step-by-step explanation:

U already solve this

We have to do e only 3 steps after last line

Answer 2

Answer:

u already slove this problem

Step-by-step explanation:

= 2x (4x2 - 9y2)

= 2x [(2x)2 – (3y)?]

= 2x (2x + 3y) (2x - 3y)

-36 = 3 (x2 + 4x – 12)

= 3 (x2 + 6x - 2x – 12)

3 [x(x + 6) -2(x + 6)]

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