Question

xy³=2, find dy/dx




plz answer me​

Answer 1

Step-by-step explanation:

xy^3=2

y=xy^3-2

differentiate with respect to x,

dy/dx=d/dx(xy^3)-d/dx(2)

=[x*3y^2+y^3*1]-0

=(y^3+3xy^2)

dy/dx= y^2(y+3x)