Question

[xyz-4] [ayz-2]
solve using algebraic identities ​

Answer 1

Answer:

$(xyz - 4)(ayz - 2) \\ = a \times x \times y \times y \times z \times z \times ( - 4) \times ( - 2) \\ = ax {y}^{2} {z}^{2} \times 8 \\ = 8ax {y}^{2} {z}^{2}$

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