∆XYZ~∆DEF, XY=5.1cm. YZ=3.9, XZ=6cm, XY:DE=3.2 construct ∆XYZ, and ∆DEF
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Answer :
XYZ-DEF
XY:DE=3:2
THEREFORE
YZ:EF=3:2 &
XZ:DF=3:2
let x=DE
3/2=5.1/x
x=5.1×2/3
x=10.2/3
x=3.4
XY=3.4cm
let y=EF
3/2=3.9/y
y=3.9×2/3
y=7.8/3
y=2.6cm
let z=DF
3/2=6/z
z=6×2/3
z=12/3
z=4cm
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