XYZ is a right angled triangle with angle X =90°, XY=9 cm , and YZ =12 cm. OX is perpendicular to YZ. Find OX.
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answer:- ox = 9√7/4cm
step by step:-
xyz is right angled triangle with x=90°,
xy=9cm,yz=12cm
(yz)²=(xy)²+(xz)²
(12)²=(9)²+(xz)²
(xz)²=(9)²+(12)²
(xz)²=81+144
(xz)²=225
xz= 3√7
erea of triangle ∆xyz=(1/2)xy×xz=
(1/2)yz×ox
=⟩xy×xz=yz×ox
=⟩9×3√7=12×ox
=⟩ox=9√7/4
:•ox=9√7/4cm
hope this answer is helpful
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