XYZ is a right angled triangle with angleX = 90 degree, XY = 9 cm, andYZ = 12 cm. OX is perpendicular to YZ findOX
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from given
∆XYZ and ∆OXZ are similar triangles
because, XZ is common, angle X in ∆XYZ and angle O in ∆OXZ are right angles and angle z is common in both ∆s.
two angles and one side proves triangles are similar.
with this we can say
OX/XY= XZ/YZ
for XZ use Pythagoras theorem,
XZ²= YZ²- XY²= 12²- 9²= 144- 81= 63
XZ= √(63)= 3√7
Now, OX= XZ×XY/YZ
OX= 3√7× 9/ 12= 27√7/12= (9√7)/4 cm
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