Question

XYZ is a triangle, right angled at Y.if YZ = 8cm and XY = 15cm,find XZ.
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Answer 1

Answer:

17cm

Step-by-step explanation:

in xyz:

angle xyz = 90 degrees

by Pythagoras theorem

xz^2 = xy^2 + yz^2

= 15^2 + 8^2

= 225 + 64

= 289

xz = 17cm

Answer 2

Answer:

The value of XZ will be 17cm.

Step-by-step explanation:

Given: YZ = 8cm and XY = 15cm

We have to find the value of XZ.

• As we know, the Pythagoras theorem states that the area of the square whose side is the hypotenuse is equal to the sum of the areas of the squares on the other two sides.

That is,$a^{2}+b^{2}=c^{2}$

Where,

$\begin{array}{l}a=\text { side of a right triangle } \\b=\text { side of a right triangle } \\c=\text { hypotenuse }\end{array}$

We are solving in the following way:

We have,

The given triangle is a right angle triangle and YZ = 8cm and XY = 15cm.

So, the value of XZ will be:

$XY^2+YX^2=XZ^2\\=>15^2+8^2=XZ^2\\=>225+64=XZ^2\\=>289=XZ^2\\=>XZ=\sqrt{289} \\=>XZ=17\ \ ...[17\times17=289]$

So, the value of XZ will be 17cm.