Question

XYZ is a triangle, right angled at Z. If XY = 17 cm and XZ-15 CM, find YZ. 14. In the given figure, PQ || RS and PQ-RS. Prove that A POQ = ASOR​

Answer 1

Answer:

Solution:-

Given:-

PQ∥RS

To prove:- △POQ∼△SOR

Proof:-

In △POQ and △SOR

∠POQ=∠SOR[∵Vertically opposite angles]

∠P=∠S[∵As PQ∥RS, Alternate angles]

∠Q=∠R[∵As PQ∥RS, Alternate angles]

Using AAA similarity function criteria,

△POQ∼△SOR

Hence proved.

solution

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Solve any question of Triangles with:-

Answer 2

Answer:

∘

Step-by-step explanation:

YZ=x,XZ=2x,∠Y=90

∘

By using Pythagoras theorem

XZ

2

=XY

2

+YZ

2

XY

2

=XZ

2

−YZ

2

=(2x)

2

−(x)

2

=4x

2

−x

2

=3x

2

∴XY=

3x

2

=

3

x

From ΔXYZ

tanx=

XY

YZ

=

3

x

x

=

3

1

=tan30

∘

⇒∠YXZ=30

∘

tanz=

YZ

XY

=

x

3

x

=

3

=tan60

∘

⇒YZX=60

∘

∴∠YXZ=30

∘

and ∠YXZ=60