Question

Xyz is right angle at vertex x. if xy = 15 cm , z x= 20 cm , find YZ​

Answer 1

By Pythagoras theorem,

$\sf {{YZ}^{2} = {ZX}^{2} + {YX}^{2} }$

$\sf {{YZ}^{2} = {(20)}^{2} + {(15)}^{2} }$

$\sf {YZ = \sqrt{400 + 225} }$

$\sf {YZ = \sqrt{625} }$

$\sf { \underbrace{\underline{YZ = 25}}}$

Hence, the answer is 25 cm.

Answer 2

By Pythagoras theorem,

\sf {{YZ}^{2} = {ZX}^{2} + {YX}^{2} }YZ

2

=ZX

2

+YX

2

\sf {{YZ}^{2} = {(20)}^{2} + {(15)}^{2} }YZ

2

=(20)

2

+(15)

2

\sf {YZ = \sqrt{400 + 225} }YZ=

400+225

\sf {YZ = \sqrt{625} }YZ=

625

\sf { \underbrace{\underline{YZ = 25}}}

YZ=25

Hence, the answer is 25 cm.

Answer:

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