Question

xyz is right angled triangle with x=90°,xy=9cm and yz=12cm.ox is purpendicular to yz find ox. Answer is 7.2.please find​

Answer 1

Answer:

The length of perpendicular OX is 5.47cm.

Step-by-step explanation:

Consider right angled triangle XYZ right angled at B.

YZ is the hypotenuse.

By Pythagoras theorem,

$h^{2}$ = $a^{2}$ + $b^{2}$

$YZ^{2}$ = $XY^{2}$ + $XZ^{2}$

$12^{2}$ = $9^{2}$ + $XZ^{2}$

144 = 81 + $XZ^{2}$

144 - 81 = $XZ^{2}$

$XZ^{2}$ = 63

XZ = $\sqrt{63}$

XZ = 7.93 cm

Area of triangle = $\frac{1}{2}$ x b x h

                          = $\frac{1}{2}$ x 9 x 7.93

                          = 32.85$cm^{2}$

So the area of ΔXYZ is 32.85$cm^{2}$.

Area of triangle =  $\frac{1}{2}$ x b x h

32.85  =  $\frac{1}{2}$ x 12 x OX

32.85 = 6 x OX

$\frac{32.85}{6}$ = OX

OX = 5.47 cm..