∆XYZ~∆ PQR and LX=55°,LQ=77°, then find angle Z
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Answer:
110°
Step-by-step explanation:
In triangle PQR using angle sum property of triangle
Triangle P + triangle Q + triangle R =180°
Triangle P +50°+70°=180°
Triangle p=180°-120°=60°
Now triangle PQR~triangle XYZ
As corresponding angles of similar triangles are equal
Triangle X = triangle P =60°
Triangle Y = triangle Q =50°
Triangle X + triangle Y =60°+ 50°= 110
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