Question

∆xyz~∆pqr,yz=11.2cm,qr=15.4cm.if the are of the∆xyz=64cm²,then find the area of the∆pqr.

Answer 1

A(∆XYZ)÷A(∆PQR)=YZ^2÷QR^2

64÷ A(∆PQR)=11.2^2÷15.4^2

A(∆PQR)=237.16×64÷125.44

A(∆PQR)=121