Δ XYZ ≅Δ RST and XY=7 cm, YZ= 2.7cm , ZX=6 cm, What is the length of TR?
Answers
Step-by-step explanation:
Construct ΔPQR, in which QR = 4.2cm m∠Q = 40∘ and PQ + PR = 8.5cm
ANSWER:
Steps of constructions:
(1) Draw seg QR of length 4.2 cm.
(2) Draw ray QT such that ∠RQT = 40°.
(3) Mark point S on ray QT such that QS = 8.5 cm
(4) Draw seg RS.
(5) Construct the perpendicular bisector of seg RS .
(6) Name the point of intersection of ray QS and the perpendicular bisector of RS as P.
(7) Draw seg PR.
Therefore, △ABC is the required triangle
Page No 53:
Question 2:
Construct Δ XYZ, in which YZ = 6 cm, XY + XZ = 9 cm. ∠XYZ = 50∘
ANSWER:
Steps of constructions:
(1) Draw seg YZ of length 6 cm.
(2) Draw ray YV such that ∠ZYV = 50°.
(3) Mark point W on ray YV such that YW = 9 cm
(4) Draw seg WZ.
(5) Construct the perpendicular bisector of seg WZ .
(6) Name the point of intersection of ray YW and the perpendicular bisector of WZ as X.
(7) Draw seg XZ.
Therefore, △XYZ is the required triangle.