XZ=9m
YZ=9m
Find the value of OX which is perpendicular to the YZ.
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xzo is a right angle so by Pythagoras theoram we can find ox ..as ox is a bisector so oy=zo
oy=zo=6
xo²= xz 2-oz²
xo²=9²-6²=81-36 =45
xo=√45
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XZ=9m
YZ=9m
Find the value of OX which is perpendicular to the YZ.
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