Question

y=0.2 sin pi (0.02x-2t) find the value of a,frequency,and wave number

Answer 1

Answer:

0.2m, 1Hz, 1cm

Step-by-step explanation:

y=0.2 sin pi (0.02x-2t)

wave eqn : y = A sin (kx - wt)

k = 2π/lambda ; w = 2π/T

given eqn : 0.2 sin (π0.02x-2πt)

hence....

amplitude : A = O.2 m

wave number : 1/lambda = 0.02/2 = 0.01m = 1cm

frequency : 1/T = 2π/2π = 1Hz