Question

y+1-(2y+3)/3-2y=1/4​

Answer 1

Step-by-step explanation:

its yur solution dear...

Answer 2

Step-by-step explanation:

Given equation is [(y+1)-(2y+3)]/(3-2y) = 1/4

=> (y+1-2y-3)/(3-2y) = 1/4

=> (-y-2)/(3-2y) = 1/4

On applying cross multiplication then

=> 4(-y-2) = 1(3-2y)

=> -4y-8 = 3-2y

=> -4y+2y = 3+8

=> -2y = 11

=> y = 11/-2

Therefore y = -11/2

The value of y for the given problem is -11/2