(y+1)-(2y+3)/3-2y=1/4 solve the equation
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Step-by-step explanation:
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Answered by
1
Step-by-step explanation:
Given equation is [(y+1)-(2y+3)]/(3-2y) = 1/4
=> (y+1-2y-3)/(3-2y) = 1/4
=> (-y-2)/(3-2y) = 1/4
On applying cross multiplication then
=> 4(-y-2) = 1(3-2y)
=> -4y-8 = 3-2y
=> -4y+2y = 3+8
=> -2y = 11
=> y = 11/-2
Therefore y = -11/2
The value of y for the given problem is -11/2
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