Question

{y-1)/3}-{(y-2)/4}=1
linear equations in one variable rs Aggarwal​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$( \frac{y - 1}{3} ) - ( \frac{(y - 2)}{4} ) = 1 \\ \frac{y - 1}{3} - \frac{y + 2}{4} = 1 \\ \frac{4y - 4 - 3y + 6}{12} \\ \frac{4y - 3y - 4 + 6}{12} \\ \frac{y + 2}{12} = 1 \\ y + 2 = 12 \\ y = 10$

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