Math, asked by kumar489339, 4 months ago

y-1/3-y-2/4=1 solve please ​

Answers

Answered by swapnamatoor
3

Step-by-step explanation:

Answer

3

y−1

4

y−2

=1

12

4y−4−3y+6

=1

⇒y+2=12

⇒y=10.

Answered by tennetiraj86
1

Step-by-step explanation:

Given:-

(y-1)/3-(y-2)/4=1

To find :-

Solve the given equation?

Solution:-

Given equation is (y-1)/3-(y-2)/4=1

LCM of 3 and 4 = 12

=> [4(y-1) -3(y-2)]/12 = 1

=> (4y-4-3y+6)/12 = 1

=> (y+2)/12 = 1

=> y+2 = 1×12

=> y+2 = 12

=> y = 12-2

=> y = 10

Therefore, y = 10

Answer:-

The solution for the given equation is 10

Check:-

If y=10 then

LHS = (y-1)/3-(y-2)/4

=> (10-1)/3 - (10-2)/4

=> (9/3) -(8/4)

=> 3-2

=> 1

=> RHS

LHS = RHS is true for y = 10

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