y+1/4y=2 then 16y³+1/4y³=
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ANSWER
ANSWERGiven p(y)=4y3+4y2−y−1 is a multiply of (2y+1)
ANSWERGiven p(y)=4y3+4y2−y−1 is a multiply of (2y+1)To check that 2y+1 is the factor the value of 2y+1=0 so y=−21
ANSWERGiven p(y)=4y3+4y2−y−1 is a multiply of (2y+1)To check that 2y+1 is the factor the value of 2y+1=0 so y=−21So put y=−21 in expression we get
ANSWERGiven p(y)=4y3+4y2−y−1 is a multiply of (2y+1)To check that 2y+1 is the factor the value of 2y+1=0 so y=−21So put y=−21 in expression we getp(−21)=4(−21)3+4(−21)2−(−21)−1
ANSWERGiven p(y)=4y3+4y2−y−1 is a multiply of (2y+1)To check that 2y+1 is the factor the value of 2y+1=0 so y=−21So put y=−21 in expression we getp(−21)=4(−21)3+4(−21)2−(−21)−1⇒p(−21)=4×−81+4×41−21−1
ANSWERGiven p(y)=4y3+4y2−y−1 is a multiply of (2y+1)To check that 2y+1 is the factor the value of 2y+1=0 so y=−21So put y=−21 in expression we getp(−21)=4(−21)3+4(−21)2−(−21)−1⇒p(−21)=4×−81+4×41−21−1⇒p(−21)=21+1−21−1
ANSWERGiven p(y)=4y3+4y2−y−1 is a multiply of (2y+1)To check that 2y+1 is the factor the value of 2y+1=0 so y=−21So put y=−21 in expression we getp(−21)=4(−21)3+4(−21)2−(−21)−1⇒p(−21)=4×−81+4×41−21−1⇒p(−21)=21+1−21−1⇒p(−−21)=0
−21)=0So remainder is zero when 2y-1 divided polynomial 4y3+4y2−y−1
−21)=0So remainder is zero when 2y-1 divided polynomial 4y3+4y2−y−1 Then 2y+1 is a multiple or factor of polynomial 4y3+4y2−y−1