Question

y=1-cosx find dy/dx​

Answer 1

Answer:

$\frac{dy}{dx} = \frac{d}{dx} (1 - \cos \: x) \\ \frac{dy}{dx} = \frac{d}{dx} (1) - \frac{d}{dx} ( \cos x\:)\\ \frac{dy}{dx} = 0 + \sin \: x \\ \frac{dy}{dx} = \sin \: x$

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Answer 2

Answer:

y' = sin x

Step-by-step explanation:

Given :

y = 1 - cos x

We are asked to find d y / d x

Now diff. w.r.t. x

d y / d x = d / d x ( 1 - cos x  )

d y / d x = y' = d / d x ( 1 ) - d / d x ( cos x )

y' = 0 - ( - sin x )

y' = sin x

Therefore , d y / d x of y =  1 - cos x  is sin x .