Question

Y+1 is a factor of 2y2+ky then the value of k

Answer 1

Answer:

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Let the polynomial be p(y) = 2y² +ky

Given that,

(y + 1) is a factor of the polynomial p(y). So, y = -1

➡ 2y² + ky = 0

➡ 2(-1)² + k(-1) = 0

➡ 2(1) -k = 0

➡ 2 - k = 0

➡ 2 - 0 = k

➡ k = 2

Therefore, the value of k is " 2 ".

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Step-by-step explanation:

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